Question 367782
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Hi,
*Note: vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
{{{ f(x)=(x-1)^2+2 }}}vertex is (1,2) which is a minimum as 'a' = 1 (a >0 parabola opens upward)

{{{graph( 300, 300,-6,6,-6,6,(x-1)^2 + 2) }}}