Question 367783
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Hi,
*Note: vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
{{{ f(x)=(x+3)^2-2 }}}
vertex is (-3,-2) which is a minimum as 'a' = 1 (a >0 parabola opens upward)

{{{graph( 300, 300,-6,6,-6,6,(x+3)^2 - 2) }}}