Question 367608
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Hi, 
*Note: the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
f(x) = x^2 + 6x + 18
completing the square
f(x) =(x+3)^2 -9 + 18 = 1*(x+3)^2 + 9
 a = 1, a positive number, therefore parabola opens upward
vertex is (-3,9) this is a minimum value.
{{{graph( 300, 300,-15,15,-15,15,x^2 + 6x + 18) }}}