Question 367638
Solve equation: x^2+4x+3=0
(x+3)(x+1) = 0

If (x+3) = 0
      x  = -3

If (x+1) = 0
      x  = -1
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-8q^2-2q+1=0
(-4q + 1)(2q + 1) = 0
If (-4q + 1) = 0
          q  = 1/4
If (2q + 1) = 0
          q = -1/2