Question 367153
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Hi, 
Not sure exactly what the focus is here:
finding the vertex
The vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
y = {{{2x^2+16x+9}}}
y = 2[(x^2 + 8x + 9/2)]
y = 2[(x+4)^2 -16 + 9/2)]
y = 2(x+4)^2 + 2*(-23/2)
y = 2(x+4)^2 - 23
vertex (-4,-23)

{{{graph( 300, 300,-30,30,-30,30,2x^2 +16x +9) }}}