Question 40763
Hello!
First of all, since you have one "a" in all the terms, you can use it as common factor:

{{{a(2a^2 - 52*a*b + 96*b^2)}}}

Also, notice that all the terms inside the parenthesis are even. Therefore, we can also take 2 as common facor:

{{{2a(a^2 - 26*a*b + 48*b^2)}}}

Finally, the remaining terms inside the parenthesis {{{(a^2 - 26*a*b + 48*b^2)}}} can be factored as:

{{{(a - 2b)(a-24b)}}}

Therefore, the whole expression can be factored as:

{{{2a(a-2b)(a-24b)}}}


I hope this helps!
Get more answers at <a href=http://www.onlinemathanswers.com>Online Math Answers.com</a>!