Question 367065
since P(A)P(B) = P(A&B) A and B are independent, hence the probability of A knowing B is the same as A, or
 
P(A|B) = P(A) = 0.5
 
 
Other way : P(A&B) = P(A|B)P(B), this implies : .3 = P(A|B)*0.6
 
-> P(A|B) = .3/.6 = 1/2 = 0.5