Question 366837
{{{(x+1)(x-2)(2^x) > 0 }}}.
The factor {{{2^x >0}}} for all real values of x, and so we can just eliminate it from the inequality by dividing both sides by it.  Hence we're actually solving 
{{{(x+1)(x-2)> 0 }}}.  The critical numbers are -1 and 2. Choosing test numbers x = -2, 0 and 3, we find out that the solution set is ({{{-infinity}}}, -1)U(2, {{{infinity}}}).