<PRE><B>Question 366980</B>
A sample of 4 different calculators is randomly selected from a group containing 18 that are defective. and 35 with no defects. What is the probability that at least 1 calculator is defective.
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Binomial Problem with n = 4 and P(defective) = 18/(18+35) = 18/53
And P(not defective) = 35/53
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P(at least one defective) = 1 - P(none defective)
P(at least one defective) = 1 - (35/53)^4 = 0.8098
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Cheers,
Stan H. 
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