Question 40761
 
 {{{16x^2+40xy+25y^2}}} 
 
 = {{{16x^2+20xy+20xy+25y^2}}}
 
 = {{{4x(4x+5y)+5y(4x+5y)}}}.  Now taking out the common factors, we get,
 
 = {{{(4x+5y)*(4x+5y)}}}  Answer.
  
gsm