Question 366959
{{{f(x)=a(x-8)(x+4)}}}
{{{f(x)=a(x^2-4x-32)}}}
Convert to vertex form,
{{{f(x)=a(x^2-4x)-32a}}}
{{{f(x)=a(x^2-4x+4)-32a-4a}}}
{{{f(x)=a(x-2)^2-36a}}}
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{{{-36a=-6}}}
{{{a=1/6}}}
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{{{f(x)=a(x^2-4x-32)}}}
{{{f(x)=(1/6)(x^2-4x-32)}}}
{{{highlight(f(x)= (1/6)x^2-(2/3)x-(16/3)) }}}

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{{{drawing(300,300,-10,10,-10,10,circle(8,0,0.3),circle(-4,0,0.3),circle(2,-6,0.3),grid(1),graph(300,300,-10,10,-10,10,0,(1/6)x^2-(2/3)x-(16/3)))}}}