Question 366929
From {{{6t^2-7t}}} we can see that {{{a=6}}}, {{{b=-7}}}, and {{{c=0}}}



{{{D=b^2-4ac}}} Start with the discriminant formula.



{{{D=(-7)^2-4(6)(0)}}} Plug in {{{a=6}}}, {{{b=-7}}}, and {{{c=0}}}



{{{D=49-4(6)(0)}}} Square {{{-7}}} to get {{{49}}}



{{{D=49-0}}} Multiply {{{4(6)(0)}}} to get {{{(24)(0)=0}}}



{{{D=49}}} Subtract {{{0}}} from {{{49}}} to get {{{49}}}



So the discriminant is {{{D=49}}}



Since the discriminant is greater than zero, this means that there are two real solutions.



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