Question 366589
In general, if f(x) has the inverse *[Tex \LARGE f^{-1}(x)] and the point (a,b) lies on the graph of f(x) (ie f(a)=b), then the point (b,a) lies on the graph of *[Tex \LARGE f^{-1}(x)] (since *[Tex \LARGE f^{-1}(b)=a] 



So if the graph of f(x) contains (-16,-3), then *[Tex \LARGE f^{-1}(x)] contains the point (-3,-16)