Question 40742
{{{6x^2 + 7x - 20 = 0}}}
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-7 +- sqrt( (7)^2-4*(6)*(-20) ))/(2*(6)) }}}
{{{x = (-7 +- sqrt( 49 + 480 ))/(12) }}}
{{{x = (-7 +- sqrt(  529 ))/(12) }}}
{{{x = (-7 +- 23)/(12) }}}
{{{x = -2.5}}} or {{{x = 4/3}}}
or
*[invoke quadratic "x", 6, 7, -20]