Question 366439
Assume that the population of heights of male college students is approximately normally distributed with mean m of 73.63 inches and standard deviation s of 6.73 inches. A random sample of 97 heights is obtained. 
a. Find the mean and standard error of the xbar distribution.
mean of the sample means = 73.63
std of the sample means = 6.73/sqrt(97)
-----------------------------
b. Find P(xbar > 73.50)
t(73.50) = (73.50-73.63)/[6.73/sqrt(97)] = -0.1902
P(xbar > 73.50) = P(t> -0.1902 when df = 96) = 0.5752
==================
Cheers,
Stan H.