Question 366323
1. {{{(y-3)^2(y-3-1) = 0}}},
{{{(y-3)^2(y-4) = 0}}}.  Therefore, the roots are 4  or 3 (multiplicity 2).

2.  {{{2t^4 - 5t^2 + 3 = 0}}},
{{{(2t^2-3)(t^2-1) = 0}}}, therefore the roots are 1,-1, {{{sqrt(3/2)}}}, or {{{-sqrt(3/2)}}}.