Question 366154
ln x + ln (x+7) = -5 
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Since ln(A) + ln(B) = ln(AB)
you get:
ln[x(x+7)] = -5
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That means "the exponent of "e" that gives you
x^2+7x is -5"
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Solve x^2+7x = e^-5
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x^2 + 7x = 0.0067
x^2 + 7x - 0.0067 = 0 
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Positive solution:
I graphed the equation and found zeroes at
x = 9.57x10^-4
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Cheers,
Stan H.
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