Question 366079
{{{ (1+x)^(82/365) = (1+.080)^(175/365) / (1+.012)^(93/365)}}}
.
.
{{{ 1+x= (1+.080)^((175/365)*(365/82)) / (1+.012)^((93/365)*(365/82))}}}
.
.
{{{ 1+x= (1+.080)^(175/82) / (1+.012)^(93/82)}}}
.
.
{{{ highlight(x= (1+.080)^(175/82) / (1+.012)^(93/82)-1)}}} or approximately
{{{ x=0.1627}}}