Question 366084
Let's write it using the program as
{{{5/(5a+10) - 7/(6a+12)}}}
Now let's factor both denominators to get
{{{5/(5(a+2)) - 7/(6(a+2))}}}
We need to somehow find a common denominator...
We can cancel the fives out in the first term and then multiply top and bottom by 6, and get...
{{{1/(a+2) - 7/(6(a+2))}}} =
{{{6/(6(a+2)) - 7/(6(a+2))}}} =
{{{-1/(6(a+2))}}}