Question 40666
steve traveled 600 miles at a certain speed. had he gone 20mph faster, the trip would have taken 1 hour less.  Find the speed of his vehicle.

1st trip Data:
distance = 600 miles; Rate= x mph; Time= 600/x hrs.

2nd trip Data:
Distance=600 miles;Rate=(x+20)mph; Time=600/(x+20)

EQUATION:
1st trip time = 2nd trip time +1 hr.
600/x = 600/(x+20) + 1

600(x+20)=600x+x(x+20)
600x+12000=600x+x^2+20x
x^2+20x-12000=0
(x+120)(x-100)=0
x=100 mph (Speed of Steve's vehicle on the 1st trip)
Cheers,
Stan H.