Question 365982
Use a common denominator, {{{(5x+4)(x+2)}}}
{{{((x-1)(x+2))/((5x+4)(x+2))=(2(5x+4))/((5x+4)(x+2))}}}
{{{((x-1)(x+2)-2(5x+4))/((5x+4)(x+2))=0}}}
{{{(x^2+x-2-10x-8)/((5x+4)(x+2))=0}}}
{{{(x^2-9x-10)/((5x+4)(x+2))=0}}}
{{{((x+1)(x-10))/((5x+4)(x+2))=0}}}
Two solutions:
{{{x+1=0}}}
{{{highlight(x=-1)}}}
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{{{x-10=0}}}
{{{highlight(x=10)}}}