<PRE><B>Question 5146</B>
I think I did this one right
solve by factoring
5x^2-19x+18=0 
5x^2-10x-9x+18=0
5x(x-2)-9(x-2)=0


Factor out the common factor of (x-2)
(x-2)(5x-9)= 0
x-2=0 5x-9=0 

The next step is incorrect:
x=2 x=1/4 


Where did you get x= 1/4???


Second answer should be: 
5x-9 = 0 
5x = 9
x= 9/5


R^2 at SCC</PRE>