Question 365946
Let r = radius of the bigger circle.  Then {{{(pi*r^2)/(9pi) = 40}}}.
{{{r^2/9 = 40}}}, or {{{r^2 = 360}}}.  Hence {{{r =6*sqrt(10)}}}.  Thus the circumference of the bigger circle is {{{C = 2pi*r = 2*pi*6sqrt(10) = 12*pi*sqrt(10)}}} meters.