<PRE><B>Question 365871</B>
if a plane leaves at noon traveling at 180 mph and another plane leaves at 1 pm traveling at 330 mph, how long until they are even?
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Noon plane DATA:
rate = 180 mph ; time = x hrs ; distance = 180x miles
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1 pm plane DATA:
rate = 330 mph ; time = x-1 hr ; distance = 330(x-1) miles
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Equation:
distance = distance
180x = 330x-330
-150x = -330
x = 2.2 hrs = 2 hrs 12 minutes (time it will take for the 1pm to catch the noon)
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Cheers,
Stan H.
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