Question 365761

A) Factor the exression.
1. 121^2-25 
my attempt. i got -3025 with 55times-55 but I dont think tats right. 
<pre><font color = "indigo"><b>
    121² - 25
    121² - 5²
(121 - 5)(121 + 5)   <--- that's factored

    (116)(126)
      14616


</pre></font></b>
B) Simplify the expression.
<pre><font color = "indigo"><b>

 {{{3sqrt(8)sqrt(18)}}}

 {{{3sqrt(4*2)sqrt(9*2)}}}
  
 {{{3sqrt(4)sqrt(2)sqrt(9)sqrt(2)}}}

 {{{3*2*sqrt(2)*3*sqrt(2)}}}
 
 {{{3*2*3*(sqrt(2))^2}}}

 {{{3*2*3*2}}}

 {{{36}}}    

</pre></font></b>
(I wasnt at school the day we learned this so I'm clueless) 
c) solve the equation.
{{{3x^2-100=332}}} 
{{{3x^2 = 332+100}}}
{{{3x^2 = 432}}}
{{{x^2 = 144}}}
{{{x = "" +- sqrt(144)}}}
{{{x = "" +- 12}}}
  
My question is, is what method do I use to solve the equation? 
<pre><font color = "indigo"><b>

The principle of square roots.

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D) perform the given operation.
<pre><font color = "indigo"><b>

1-2i
----
3-5i 

multiply by the conjugate of the bottom over itself

1-2i  3+5i   3+5i-6i-10i²   3-i-10i²    3-i-10(-1)   3-i+10   13-i
----. ---- = ------------ = --------- = ---------- = ------ = ---- =  
3-5i  3+5i   9+5i-5i-25i²    9-25i²      9-25(-1)     9+25     34

{{{13/34-expr(1/34)i}}}

Edwin</pre>