<PRE><B>Question 365619</B>
Peter,Sam,Sandy and Isabel work at a kennel.Peter gives the baths the dogs every 4 days;Sam cleans the cages every 6 days;Sandy feeds the animals every 2 days;ans Isabel helps mop the floor every 3 days.How many times in 12 weeks will all 4 helpers be at the kennel?
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12 weeks has 7*12 = 84 days
Find the least common multiple of 4,6,2,and 3
It is 12
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Assume they all work together on day #1.
They will work together again on day 13,25,37,49,61, and 73
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Cheers,
Stan H.</PRE>