Question 365548
Solve the following equation with the method of your choice: 

y/3y-4 = 2/y+4
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Cross-multiply to get:
y(y+4) = 2(3y-4)
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y^2+4y = 6y-8
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y^2 -2y + 8 = 0
(y-4)(y+2) = 0
y = 4 or y = -2
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Cheers,
Stan H.
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