<PRE><B>Question 365546</B>
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Hi, 
*Note: exploring the factors of -2, found that x = 2 works       

          x^2 + 3x + 1
        __________________________
x - 2 | x^3 +  x^2  - 5x  -  2
      - (x^3 -2x)
       ---------------
                3x -  5x
             - (3x -  6x)
                ---------
                      x  - 2
                  - ( x  - 2)
                     ---------
                           0
x^2 + 3x + 1
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-3 +- sqrt( 5 ))/(2) }}}
x = 2 and {{{x = (-3 +- sqrt( 5 ))/(2) }}}

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