Question 365461
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Hi, 
***General point-slope from of an equation is 
y = mx + b where m is the slope and b is the value of y where the line crosses the y-axis
7x+10y=4.5
y = (-7/10)x + 4.5/10 
0 = (-7/10)x + 4.5/10      x-intercept is when y = 0
{{{(-4.5/10)*(10/-7) = (45/70) = 9/ 14 = x}}}
 x-intercept = (9/14)

Slope of the new line 1s 10/7
( perpendicular lines have slopes that are negativie reciprocals of one another)
10/7 is the negative reciprocal of -7/10
y = (10/7)x + b
Using ordered pair ((9/14),0) to solve for b
{{{ 0 = (10/7)* (9/14) + b }}}
.918 = b
y = (10/7)x + .918
{{{graph( 300, 300,-6,6,-6,6,grid(1),(10/7)x + .918,(-7/10)x + .45 ) }}}