Question 365377
 when complete. He is mixing a 24% solution with a 50% solution to get a 36% solution. How many gallons of each will he use?
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x gallons ------------ 24%
(100-x)gallons ------- 50%
Mixture =  100 gallons--36%
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0.24x+(100-x)*0.5 = 0.36*100
0.24x+50-0.5x=36
0.24x-0.50x=36-50
-0.26x=-14
/0.26
x=  53.8 gallons of 24%
46.2  gallons of 50%
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m.ananth@hotmail.ca