Question 365389
Find two consecutive integers such that the sum of five times the smaller and three times the largers is 67
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let x, x+1 be the integers
5 times smaller = 5x
3 times bigger = 3(x+1)
..
5x+3(x+1)=67
5x+3x+3=67
8x+3=67
8x=67-3
8x=64
/8
x= 8 
8,9 are the integers
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