Question 40630
  Here, in your problem, p(x) = {{{3t^2+5t-7}}} and the divisor = {{{t-5}}}.
  So we take x = 5 and by the reminder theorem, the reminder is:
  p(5) = {{{3(5^2)+5(5)-7}}} = 3(25)+25-7 = 75+25-7 = 100-7 = 93.
 = by the reminder theorem, the  reminder = p(5) = 93.  Answer.

gsm