Question 364885
This metal alloy is composed of 90% tin, 7% antimony, and 3% copper.
 How many ounces of pure tin must be added to the alloy to make 6 ounces
 of a metal that is 94% tin?
:
Do this on the basis of percent tin, we can ignore the other elements in the equation
:
Let x = amt of pure tin to be added
then
(6-x) = amt of 90% tin required
:
.90(6-x) + x = .94(6)
5.4 - .9x + x = 5.64
-,9x + x = 5.64 - 5.4
.1x = .24
x = {{{.24/.1}}}
x = 2.4 oz of pure tin to be added to 3.6 of the original alloy