Question 364834
A runner decides to run out in the country.
 He begins to run at an average rate of 9 miles per hour.
 He runs a certain distance and then turns around and returns along the same
 route at an average rate of 6 miles per hour.
 If the round trip took two and a half hours, how far did the runner travel
 before turning around?
:
Let d = one-way distance (point of turning around)
:
Write a time equation: Time = dist/speed
:
outbound time + return time = 2.5 hrs
{{{d/9}}} + {{{d/6}}} = 2.5
Multiply by 18 to clear the denominators, results:
2d + 3d = 18(2.5)
5d = 45
d = {{{45/5}}}
d = 9 miles out in the country before turning around.
:
:
See if that's true
{{{9/9}}} + {{{9/6}}} = 
1 + 1.5 = 2.5