Question 364913
Dave and Cindy played 53 games of backgammon last month.
 Dave's ratio of wins to losses was 37/16.
If Dave and Cindy play 10 more games, write a proportion to determine how many
 of these 10 games dave could expect to win.
:
If the proportion remains the same for these 10 games:
{{{37/53}}} * 10 ~ 7 games
:
:
Determine how many more games Dave and Cindy must play before Cindy will have
 won a total of 28 games.
Let x = no. of additional games for this to happen
{{{16/53}}} = {{{28/((x+53))}}}
Cross multiply
16(x+53) = 28 * 53
16x + 848 = 1484
16x = 1484 - 848
x = {{{636/16}}}
x ~ 40 more games
:
:
Check this:
original per cent: 16/53 ~ .3
40 more games percent: 28/93 ~ .3