Question 364841
Since they both equal {{{y}}}, set them equal to each other.
{{{ x^3+4x= 4x^2 }}}
{{{x^3-4x^2+4x=0}}}
{{{x(x^2-4x+4)=0}}}
{{{x(x-2)^2=0}}}
Two solutions:
{{{highlight(x=0)}}}
{{{y=4(0)^2}}}
{{{highlight(y=0)}}}
.
.
{{{x-2=0}}}
{{{highlight_green(x=2)}}}
{{{y=4(2)^2}}}
{{{highlight_green(y=16)}}}
.
.
.
{{{drawing(300,300,-10,10,-2,18,circle(0,0,0.4),circle(2,16,0.4),grid(1),graph(300,300,-10,10,-2,18,0,4x^2,x^3+4x))}}}