Question 365000
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Hi, 
solve using cramer's rule
2a+3b=6
2a+b=-2
{{{D =(matrix(2,2,2,3,2,1))}}} = 2 -6 = -4
{{{D[a] =(matrix(2,2,6,3,-2,1))}}} = 6-(-6) = 12
{{{D[b] =(matrix(2,2,2,6,2,-2))}}}  = -4 -12 = -16
a = 12/-4 = -3
b = -16/-4 = 4
checking our answer
2a + b = -2
-6 + 4 = -2