Question 364968
{{{(12y^4+6y-3y^2+11y)/(3y^2)=(12y^4+6y-3y^2+11y)*(1/3)y^(-2)}}}
{{{(12y^4+6y-3y^2+11y)/(3y^2)=(12/3)y^(4-2)+(6/3)y^(1-2)-(3/3)y^(2-2)+(11/3)y^(1-2)}}}
{{{(12y^4+6y-3y^2+11y)/(3y^2)=4y^2+2y^(-1)-1y^(0)+(11/3)y^(-1)}}}
{{{(12y^4+6y-3y^2+11y)/(3y^2)=4y^2+(6/3)(1/y)-1+(11/3)(1/y)}}}
{{{(12y^4+6y-3y^2+11y)/(3y^2)=4y^2+((6+11)/3)(1/y)-1}}}
{{{highlight((12y^4+6y-3y^2+11y)/(3y^2) =4y^2+(17/3)(1/y)-1)}}}