Question 364961
Complete the square.
{{{y=x^2+7x-2}}}
{{{y=(x^2+7x+49/4)-2-49/4}}}
{{{y=(x+7/2)^2-8/4-49/4}}}
{{{y=(x+7/2)^2-57/4}}}
The vertex is ({{{-7/2}}},{{{-57/4}}}).
The vertex lies on the axis of symmetry, {{{x=-7/2}}}
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{{{drawing(300,300,-10,5,-20,5,circle(-7/2,-57/4,0.3),blue(line(-7/2,-20,-7/2,20)),grid(1),graph(300,300,-10,5,-20,5,0,x^2+7x-2))}}}