Question 364820
Bus A west 40 mph
Bus B north 30 mph 
distance 400 miles
..
let time be t
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Bus A distance traveled = 40t
Bus B distance traveled = 30 t
..
(40t)^2+(30t)^2=400^2
1600t^2+900t^2=160000
2500t^2=160000
/2500
t^2= 160000/2500
t^2=64
t=8 hours
After 8 hours
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m.ananth@hotmail.ca