Question 364808
{{{2x^2-6x-4>0}}},
{{{x^2-3x-2 > 0}}}, the critical values for this inequality are {{{(3+-sqrt(17))/2}}}, approximately 3.5616 or -0.5616.  Using test points x = -1, 0, and 4, we get the solution set to be ({{{-infinity}}}, {{{(3-sqrt(17))/2}}})U({{{(3+sqrt(17))/2}}}, {{{infinity}}})