Question 364767
Call the integers {{{n}}}, {{{n+1}}}, and {{{n+2}}}.
given:
{{{n + n + 1 + n + 2 = 126}}}
{{{3n + 3 = 126}}}
{{{3n = 123}}}
{{{n = 41}}}
{{{n + 1 = 42}}}
{{{n + 2 = 43}}}
The integers are 41, 42, and 43