Question 364625
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Hi, 
2+log base(2)4=3x-1 
log base(2)4=3x-3 
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
2^(3x-3) = 4 
2^(3x-3) = 2^2 
3x-3 = 2
3x = 5
x = 5/3