Question 40561
Let one number be x
Let another number be y
x+y=25
y=25-x (SUBSITUTION)
EQUATION:
{{{x^2-y^2=75}}}
Sub for y:
{{{x^2-(25-x)^2=75}}}
{{{x^2-(625+x^2-50x)=75}}}

50x=700
x=14
y=25-14
y=11
Hence, the two numbers are 14 and 11.
Paul.