Question 364540
{{{3y+21=2x}}}
{{{3y=2x-21}}}
{{{y[1]=(2/3)x-7}}}
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{{{2y=16-3x}}}
{{{y[2]=-(3/2)x+8}}}
The lines are not parallel since the slope need to be identical.
For the lines to be perpendicular, the slopes must be negative reciprocals,
{{{m[1]*m[2]=-1}}}
{{{(2/3)(-(3/2))=-1}}}
{{{-1=-1}}}
The lines are perpendicular.
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{{{graph(300,300,-2,10,-8,4,0,(2/3)x-7,-(3/2)x+8)}}}