Question 364293
No solution means the lines are parallel. 
The left hand sides are multiples of each other.
Find the multiplier {{{Z}}} so that,
{{{Z(2x-y)=(4x+ky)}}}
Solve for the {{{x}}} and {{{y}}} terms on both sides.
{{{x}}}:{{{2Z=4}}}, {{{Z=2}}}
{{{y}}}:{{{-Z=k}}}, {{{k=-Z=-2}}}
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{{{highlight(k=-2)}}}
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{{{graph(300,300,-10,10,-10,10,0,2x+16,(4x+3)/2)}}}