Question 364435
First find the slope of the first line by converting to slope-intercept form, {{{y=mx+b}}}.
{{{12x+3y=15}}}
{{{3y=-12x+15}}}
{{{y=-4x+5}}}
{{{m=-4}}}
Parallel lines have identical slopes,
{{{m[1]=m[2]=-4}}}
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{{{y=-4x+b}}}
Use the point (-1,7) to solve for {{{b}}}.
{{{7=-4(-1)+b}}}
{{{b=3}}}
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{{{highlight_green(y=-4x+3)}}}
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{{{drawing(300,300,-6,6,-2,8,grid(1),circle(-1,7,0.3),graph(300,300,-6,6,-2,8,0,-4x+5,-4x+3))}}}