Question 364442
A box contains four red marbles, seven white marbles and five blue marbles. If one marble is drawn at random, find the probability for each of the following: A blue marble drawn. A red or a blue marble is drawn. Neither a red nor a blue marble is drawn. 

The probality a blue marble drawn                  
     = 5/(4+7+5)     = 5/16

The probability a red or a blue marble is drawn    
     = (4+5)/(4+7+5) = 9/16

The probability neither a red nor a blue marble is drawn
     = 7 / 16