Question 364376
Find 3 consecutive odd integers such that 3 times the smallest, is 5 more than the sum of the 2nd and 3rd.
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let the three odd integers be x,x+2,x+4
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3x=x+2+x+4+5
3x=2x+11
3x-2x=11
x= 11
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11.13.15
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m.ananth@hotmail.ca