Question 364311
No function is shown.
If an object is projected vertically upward from an altitude of s0 feet with an initial velocity of v0 ft/sec, then its distance above the ground after t seconds is given by the function below. If s(2) = 136 and s(5) = 55, what are v0 and s0? (Round your answer to the nearest whole number.)
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I'll use:
s(t) = -16t^2 + vt + s0
s(2) = -64 + 2v + s0 = 136
s(5) = -400 + 5v + s0 = 55
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2v + s0 = 200
5v + s0 = 455
------------- Subtract
-3v = -255
v = 85 ft/sec
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s0 = 30 feet